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Hello Joe,
You can try using the split_part string function as below
select params, split_part(params, '/', 3) as col1, split_part(params, '/', 4) as col3, split_part(params, '/', 5) as col3, split_part(params, '/', 6) as col4 from ( select '/BJ/1/10/114/201010049' as params ) tmp
Please feel free to comment if you have further issues
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- 已提問 6 個月前
- AWS 官方已更新 2 年前
Thanks a lot. This works fine.